fandomhigh | MATHS CLASSES: Friday 28.10, FST: 16:00-18:00

MATHS CLASSES: Friday 28.10, FST: 16:00-18:00

Charlie's desk is for once not covered in papers, but in foodstuff. There's a plate with pizza slices on, a plate with cookies shaped like bats, half moons and possibly cats and cups of cocoa. He stands by the desk and smacks the hands of any student who looks like they're attempting to snitch something.

"Today's message to you all - Broots is my new TA! He'll be taking attendance and such when I'm not here, as well as helping me out with projects."

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Maia signs in

Kawalsky signed in for class and handed the Doc his note from Professor Maclay.

Re: Roster

charlieeppes.livejournal.com - 2005-10-28 15:27 (UTC) - Expand

Han signs the roster.

Angelus signs in.

Lisa signs in.

Anders signs in, with only one cup of coffee today, but a cut and slightly swollen lower lip.

Faith signs in.

*signs in*

Thomasina signs her name to the roster.

Barbossa signed in.

Wallace signed in and found a seat.

Jack signs in.

Broots signs in and tries to smile.

Alanna signs in.

Chloe signs in.

Charlie places a pizza with twelve slices on to the desk in the middle. He smiles. "You all get one slice each, and then you get to tell me how much of it you've eaten, how much you've all eaten together and how much is left. In fractals. When you've done that, you may have a second slice and do it all again with the current numbers!"

1/12 I am not sure how many people are in the class sir but I'll guess 6/12 reduced to 2/4 reduced to 1/2 for the first part...

so that would mean I have eaten 2/12 reduced to 1/6 for the second part, everyone obviously has eaten the entire pizza with nothing left over so 1, 1 whole pizza was eaten.

((ooc: refrains from doing a count laugh off the sesame street))

Re: Beginners

charlieeppes.livejournal.com - 2005-10-28 15:34 (UTC) - Expand

Re: Beginners

maias-notebook.livejournal.com - 2005-10-28 15:41 (UTC) - Expand

Faith stared at him, and then at the pizza. "You're a tease. How can I think about numbers when there's a perfectly good, non-cafeteria pizza right in front of me?" She thought for a moment. "I'd eat one, out of 12. And then, since you said that we get another piece, we ate half the pizza or less. And then my second piece would be one out of the six that might be left, and then we'd be done with the pizza. Maybe?"

Re: Beginners

charlieeppes.livejournal.com - 2005-10-28 17:25 (UTC) - Expand

Re: Beginners

http://users.livejournal.com/_gottahavefaith/ - 2005-10-28 17:32 (UTC) - Expand

Barbossa thought about it for a while.

"I be havin' one o' twelve slices. So that be...1/12, aye?"

The wheels turning in his head are pratically visible.

"If'n I git another slice, that'd be 2/12, or 1/6 o' the pizza. Thar be six students in the class, 'n we each eat 1/6 o' the pizza. Thar be no more pizza left." He grinned. "Somethin' like that, mayhaps?"

Re: Beginners

charlieeppes.livejournal.com - 2005-10-28 20:02 (UTC) - Expand

Re: Beginners

likeguidelines.livejournal.com - 2005-10-28 20:24 (UTC) - Expand

The solution to last lessons' problem:

Two players bet on the total roll of two standard dice. Player A bets that a 12 will be rolled first. Player B bets that two consecutive 7s will be rolled first. The players keep rolling until one player wins. What is the probability that A will win?

Let p be the probability that player A wins. Consider the following mutually exclusive cases, which encompass all possibilities.
• If the first roll is a 12 (probability 1/36), A wins.
• If the first roll is neither a 7 nor a 12 (probability 29/36), A wins with probability p.
• If the first roll is a 7 and the second roll is a 12 (probability 1/6 · 1/36 = 1/216), A wins.
• If the first roll is a 7 and the second roll is neither a 7 nor a 12 (probability 1/6 · 29/36 = 29/216), A wins with probability p.
• If the first and second rolls are both 7 (probability 1/6 · 1/6 = 1/36), A cannot win.

Probability p is the weighted mean of these possibilities.

So p = 1/36 + (29/36)p + 1/216 + (29/216)p.

Therefore p = 7/13.

Today's problem:

A rhombus, ABCD, has sides of length 10. A circle with center A passes through C (the opposite vertex.) Likewise, a circle with center B passes through D. If the two circles are tangent to each other, what is the area of the rhombus?

When the students turn in their solution, Charlie gives them all a halloween cookie of their choice.

Kawalsky spent the entire class struggling with the problem. He should have known this, but his math was so rusty unless it was a practical problem that he had a really hard time trying to work out the answer.

He eventually submitted something at the end of the class, complete with all of ~~his scribbles~~ his working out on paper. Kawalsky took a cookie and nibbled on it, then left class thinking about who he could talk to about tutoring him in math.. quietly.

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Beginners

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Intermediate

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Talk to Charlie